The expression relating degree of dissociation of the weak electrolyte AxBy with its van’t Hoff factor is ← Prev Question Next Question → 0 votes . A. Nov 05,2020 - The degree of dissociation (a) of a weak electrolyte, AxBy is related to van’t Hoff factor (i) by the expression [2011]a)b)c)d)Correct answer is option 'A'. JIPMER 2016: The degree of dissociation (α) of a weak electrolyte AxBy is related to vanâ t Hoff factor (i) by the expression (A) α=(i-1/x+y-1) | EduRev JEE Question is disucussed on EduRev Study Group by 182 JEE Students. The degree of dissociation (α) of a weak electrolyte ,A x B y is related to van't Hoff factor (i) by the expression. Chemistry Questions & Answers for AIEEE : The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression: 1. α=x+y+1 The degree of dissociation of a weak electrolyte AxBy is related to van t Hoff factor i by the expression 665 Views. /questions/the-degree-of-dissociation---of-a-weak-electrolyte-axby-is-related-to- asked Jun 22, 2019 in Chemistry by Helisha (68.7k points) recategorized Jun 22, 2019 by Helisha. Like I know that at infinite dilution the concentration of solution is 0 but what does that have to do with degree of dissociation, secondly in oswald's law of dilution we already assume that dissociation is almost negligible so we can't obtain the result from that also . 41 views. Why the degree of dissociation of weak electrolyte is 1 at infinite dilution and how do we get the result? Can you explain this answer? Switch; Flag; Bookmark; 5. The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression: - 6976154 The degree of dissociation (a) of a weak electrolyte, AxBy is related to van’t Hoff factor (i) by the expression: (1)a =11++-yxi (2)a =11--+iyx (3)a =11-++iyx (4)

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